If 34.1 grams of pentane (C5H12) are burned in excess oxygen, how many grams of H2O will be produced?

Answer 1

C5H12 + 8O2 ==> 5CO2 + 6H2O

mols pentane = grams/molar mass
Using the coefficients in the balanced equation, convert mols pentane to mols H2O
Now convert mols H2O to grams. g = mols x molar mass.

Answer 2

If 21.5 grams of pentane (C5H12) are burned in excess oxygen, how many grams of H2O will be produced?