If 33.5 g of Mg(OH)2 reacted, what mass of H2O could be produced? Mg(OH)2(s) + HCl(aq) ---- MgCl2(aq) + H2O(l)

Question

If 33.5 g of Mg(OH)2 reacted, what mass of H2O could be produced? Mg(OH)2(s) + HCl(aq) ----> MgCl2(aq) + H2O(l)

DrBob222 · Answer

I have balanced the equation for you.
Mg(OH)2(s) + 2HCl(aq) ----> MgCl2(aq) + H2O(l)
mols Mg(OH)2 in 33.5 g is g/molar mass = 33.5/58.3 = estimated 0.6 but you need to confirm all of these numbers.
For every 1 mol Mg(OH)2 you get 1 mol H2O so estimated 0.6 mols H2O.
Then grams H2O = mols H2O x molar mass H2O = ?
Post your work if you get stuck.