If 309 J of heat are removed from 10.0 g of ice (specific heat = 2.06 J/g

Question

ºC) at -5.5 ºC, what is the final temperature of the ice sample?

Answer 1

-q = mass ice x specific heat ice x (Tfinal=Tinitial)
-309 = 10.0 x 2.06 x [Tf -(-5.5)]
Solve for Tf.

Answer 2

Thank you Dr. Bob

Answer 3

-20.5