If 3, x, minus, 3, y, equals, minus, 53x−3y=−5 is a true equation, what would be the value of 8, plus, 3, x, minus, 3, y8+3x−3y?

Answer 1

To find the value of 8 + 3x - 3y, we need to substitute the values of x and y into the equation -53x - 3y = -5.

From the equation, we can see that the coefficient of x is -53 and the coefficient of y is -3.

If -53x - 3y = -5 is a true equation, it means that -53 multiplied by the value of x minus 3 multiplied by the value of y would give us -5.

We can solve the equation to find the values of x and y:
-53x - 3y = -5

Rearranging the equation:
-53x = 3y - 5

Now, we can substitute the value of x from the given equation into this equation:
-53(3) = 3y - 5

Simplifying:
-159 = 3y - 5

Adding 5 to both sides:
-154 = 3y

Dividing both sides by 3:
-51.333 = y

We now have the value of y. To find the value of x, we can substitute the value of y into the equation:
-53x - 3(-51.333) = -5

Simplifying:
-53x + 154 = -5

Subtracting 154 from both sides:
-53x = -149

Dividing both sides by -53:
x = 2.8113

Now that we have the values of x and y, we can find the value of 8 + 3x - 3y:
8 + 3(2.8113) - 3(-51.333)
8 + 8.4339 + 153.999
= 170.4329

Therefore, the value of 8 + 3x - 3y = 170.4329.