If 3(w−2)=-8, what is the value of w?

5 answers

To solve for w, we need to isolate w on one side of the equation. First, let's distribute the 3 to the term inside the parenthesis:

3w - 6 = -8

Next, we will add 6 to both sides to eliminate the -6:

3w = -2

Finally, we will divide both sides by 3 to isolate w:

w = -2/3

Therefore, the value of w is -2/3.
If x=2 and t=4, what is the value of 18(x3−4)(t2+8)?
First, let's substitute the given values into the expression:

18(2^3 - 4)(4^2 + 8)

Simplifying the exponents inside the parenthesis:

18(8 - 4)(16 + 8)

Performing the arithmetic inside each set of parenthesis first:

18(4)(24)

Multiplying across:

= 18 x 4 x 24

= 1728

Therefore, the value of 18(x^3 - 4)(t^2 + 8) when x=2 and t=4 is 1728.
If x=2 and t=4, what is the value of 18(x3−4)(t2+8)?
First, let's substitute the given values into the expression:

18(2^3 - 4)(4^2 + 8)

Simplifying the exponents inside the parenthesis:

18(8 - 4)(16 + 8)

Performing the arithmetic inside each set of parenthesis first:

18(4)(24)

Multiplying across:

= 18 x 4 x 24

= 1728

Therefore, the value of 18(x^3 - 4)(t^2 + 8) when x=2 and t=4 is 1728.