If 3.50g of Na3Po4 and 6.40g of Ba(No3)2 are added together how many grams of Ba3(PO4)2 will be produced? Which is the limiting reactant?

Question

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Answer 1

1. Write the equation and balance it.
2Na3PO4 + 3Ba(NO3)2 ==> Ba3(PO4)2 + 6NaNO3
2. Convert 3.50 g Na3PO4 to moles. moles = grams/molar mass.
3. Convert 6.40 g Ba(NO3)2 to moles. Same process.
4a. Using the coefficients in the balanced equation, convert mole Na3PO4 to moles of the product.
4b. Same process, convert moles Ba(NO3)2 to moles of the product.
4c. It is quite likely that the answers in 4a and 4b will not agree which means one of them is wrong. The correct answer, in limiting reagent problems, is ALWAYS the smaller one and the reagent providing that answer is the limiting reagent.

5. Using the smaller value, convert moles of the product to grams. g = moles x molar mass.

Answer 2

Calculation