If 28.8 grams of calcium carbonate react to form 16.1 grams of calcium oxide, how many grams of carbon dioxide must simultaneously be formed?

Answer 1

molar Mass CaCO3 = 40+12+48 = 100 g/mol
CaO = 40 + 16 = 56 g/mol
CO2 = 12+32 = 44 g/mol
so
28.8 (44/100) = 12.7 grams