Asked by ally
if 25.2 g of aluminum (AW=27.0) are mixed with 125 g of sulfuric acid(MM=98.1)then how many grams of aluminum sulfate will be produced?
2Al+ 3 H2SO4 --> 3H2 + Al2(SO4)3
2Al+ 3 H2SO4 --> 3H2 + Al2(SO4)3
Answers
Answered by
bobpursley
convert aluminum to moles, and sulfuric acid to moles.
According to the balanced equation, you need 1.5 :1 moles Sulfuricacid:aluminum
If you have a ratio greater than this,aluminum is your limiting reageant.
If less, sulfuric acid is limiting.
I haven't worked those ratios, so do it.
Take the moles of your limiting reageant, if it was aluminum, you should get 1/2 those moles of Aluminum sulfate. Convert to grams.
If the limiting reageant was acid, you should get 2/3 of the moles of sulfuric acid as the moles of aluminum sulfate. Convert to grams.
According to the balanced equation, you need 1.5 :1 moles Sulfuricacid:aluminum
If you have a ratio greater than this,aluminum is your limiting reageant.
If less, sulfuric acid is limiting.
I haven't worked those ratios, so do it.
Take the moles of your limiting reageant, if it was aluminum, you should get 1/2 those moles of Aluminum sulfate. Convert to grams.
If the limiting reageant was acid, you should get 2/3 of the moles of sulfuric acid as the moles of aluminum sulfate. Convert to grams.
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