if 25.00 mL of 1.04 M Na2CO3 is diluted to .500 L, what is the molarity of Na2CO3 in the diluted solution?
2 answers
1.04 M x (25.00 mL/500 mL) = ? M.
(M1)(V1)=(M2)(V2)
convert all moles to grams and mL to L
25mL=0.025L
1.04M (0.025L)=M2 (0.500L)
0.026=M2 (0.5L)
(0.026)/(.5L)=M2
M2=0.052M NaCO3
convert all moles to grams and mL to L
25mL=0.025L
1.04M (0.025L)=M2 (0.500L)
0.026=M2 (0.5L)
(0.026)/(.5L)=M2
M2=0.052M NaCO3