If 25.0 cm3 of 0.50M sulfuric acid reacted with exactly 12.5 cm3 of sodium hydroxide, calculate the concentration of the alkali.

I first balanced the chemical equation between sulfuric acid and sodium hydroxide.
H2SO4 + 2NaOH --> 2H2O + Na2SO4
I converted the volume of sulfuric acid to litres then to mols. I multiplied by the mol ratio to get the moles of NaOH which was .025 mols then divided by the volume of the base to get 2M NaOH. Is this correct?

1 answer

yes