if 23.74ml of 0.01470M NaOH are required to completely neutralize 25.00ml of gastric juice,calculate the concentration of the hydrochloric acid[in g/L]in stomach gastric juice

Answer 1

NaOH + HCl ==> NaCl + H2O.

moles NaOH = M x L.
moles HCl = moles NaOH (since the reaction is 1 mole NaOH to 1 mole HCl).
molarity HCl = moles/L.
Post your work if you get stuck.

Answer 2

i don't know were to start

Answer 3

i dnt know were to begin