If 20mL of a 0.100 M NaOH solution are required to titrate 0.25 grams of an unknown acid, what is the equivalent mass of the acid? If the acid actually contains 3 moles of H+ per mole of acid what is the molecular mass of the acid?

Answer 1

mL x N x mew = grams.
20 x 0.1 x mew = 0.25
Solve for milliequivalent weight.

Then equivalent weight = 1000 x mew.
(molar mass/3) = equivalent weight. Solve for molar mass

Answer 2

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