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Original Question
if 4.4 moles of copper metal was deposited from a solution of Cu(NO3)2, how many electrons were involved?Asked by Andrea
If 2.7 moles of copper metal was deposited from a solution of Cu(NO3)2, how many electrons were involved?
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Answered by
bobpursleyl
2.7moles of Cu is 2.7*Avag number of atoms..
each atom takes two electrons.
electrons= 2*2.7*avagnumber
charge=electrons*chargeonOneelectron
= 2*2.7*avagnumber*1.60217657 × 10-19
current required=charge/time
Well, I have went further than the question asked. Your teacher is too easy.
each atom takes two electrons.
electrons= 2*2.7*avagnumber
charge=electrons*chargeonOneelectron
= 2*2.7*avagnumber*1.60217657 × 10-19
current required=charge/time
Well, I have went further than the question asked. Your teacher is too easy.
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