If 2.00 mL of 0.600 M NaOH are added to 1.000 L of 0.850 M CaCl2, what is the value of the reaction quotient and will precipitation occur?

I've been trying this problem over and over and haven't been able to get it. I know precipitation will not occur from my previous answer and that part was correct but not my reaction quotient.

Ksp for Ca(OH)2 is 5.02 x 10^-8.

The way to predict whether a precipitation will occur is to calculate Qsp and compare to Ksp.

Qsp = (Ca2+)(OH-)^2. Concentration of OH- will be given by (M1V1/V2) = 0.0012

Qsp = 0.850 * (.0012)^2 = 1.22*10^-6

My homework says this is not correct...