We start with the assumption that all the steam condenses and all the ice melts
.r•m+ c•m• (t-0) = λ•m + c•m• (100 – t),
where r = 334000 J/kg is the heat of fusion,
c =4180 J/kg•K,
λ = 2250000J/kg is the heat of vaporization.
Since the mass of steam = the mass of ice,
r+ c•(T-0) = λ + c•(100 – T),
Solve for T
T =279.2 oC
Since this is impossible, the initial assumption was false, the steam does not completely condense, and the ice heats up to 100 *C (this is the answer, as all matter in the system is at 100 *C)
To see how much steam condenses, we have 2250000•x=334000+4180 • 100,
where x is the proportion of steam that condenses.
x =0.334
0.334g of steam condense, since this is physically possible this is a successful check on the answer.
If 1g of steam is mixed wid 1g of ice, then what will be the resultant temperature of the mixture?
2 answers
can there be ne other answers elena??????????