If 18.4 mL of a 1.37 M aqueous KCl solution was placed in a 150-mL volumetric flask and water was added to dilute to the mark, after mixing, how many moles of KCl would be in the flask?

(with correct number of sig figs)

1 answer

mols = M x L = 1.37 x 0.0184 = ? You can have 3 significant figures in the answer.