(1/2)^(12/k) = 0.83
k = 44.64
so the half-life is 44.64 hours
And the amount left after x hours is
(1/2)^(x/44.64)
if 17 percent of a radioactive substance decays in 12 hours, what is the half-life of the substance?
Round your answer to one decimal place.
1 answer