Q = m*C*(Tf-Ti)
Q is heat
m is mass of water
C is the specific heat of water (look this up in cal/(g*C))
Tf is final temperature
Ti is initial temperature
1600 = 50*1*(Tf-10)
solve for Tf
If 1600cals of heat are added to 50g of water initally at a temperature of 10c what is the final temperature of the water?
1 answer