q = mass Ag x specific heat Ag x delta T
Solve for delta T.
If 155 J of energy is added to 18.5 g of silver, how much will the temperature rise?
Silver Specific Heat= (0.235J/g deg C)
4 answers
That's the formula I used
Delta T = 115J/18.5g(0.235J/g deg C)
= J and g cancel leaving me with deg C
=115/18.5(0.235 deg C)
=35.65 deg C
=36 deg C
my answer was wrong but I don't know correct answer
Delta T = 115J/18.5g(0.235J/g deg C)
= J and g cancel leaving me with deg C
=115/18.5(0.235 deg C)
=35.65 deg C
=36 deg C
my answer was wrong but I don't know correct answer
The correct answer is 35.6. You are allowed 3 s.f. since there are three in 155, 3 in 18.5 and 3 in 0.235. If you round to the nearest even number then 35.65 will be rounded to 35.6. Some may round to 35.7. I suspect either will be counted as correct by your database.
I figured out what I did wrong I divided by 18 and not 18.5. Thank you for your help