(Mzn*Czn*Tzn)+(Mwater*Cwater*Twater)=
Tfinal((Mzn*Czn)+(Mwater*Cwater))
If 150.0 g of Zinc at 100.0 C and 250.0g of liquid water at 10.0 C are mixed in an insulated container, what is the final temperature of the mixture? Czn= .39J/g C
Cwater= 4.184J/g C
Are we looking for the delta T?
If we are, how do you find Q (joules)
Thank you!
1 answer