how many moles of NaN3 in 15g?
Use the reaction equation to see how many moles of N2 will be produced.
Each mole occupies 22.4L at STP.
If 15.0 g of NaN3 is in a air bag, how much Nitrogen gas can be produced.
3 answers
The reaction equation i was given is...
2NaN3 ---> 2Na + 3N2
2NaN3 ---> 2Na + 3N2
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