If 13 cosP= 5 P¢ã[0,270]and 15 tan Q-8=0 for sinQ<0,evaluate: 17tanP.sinQ

1 answer

P is in QI, so if cosP = 5/13, tanP=12/5
Q is in QIII, so if tanQ = 8/15, sinQ = -8/17

17tanPsinQ = 17(12/5)(-8/17) = -96/5