If 12 people are playing in a tournament and each person plays every other person, how many games will be played?
6 answers
Mrs. Sue??
Reiny
The first person plays 11, the second plays 10, the thrid plays 9
number games=11+10+9+...+1
the sum of numbers from n-1 to 1, or
number= N*(n-1)/2=12*11/2= 66
number games=11+10+9+...+1
the sum of numbers from n-1 to 1, or
number= N*(n-1)/2=12*11/2= 66
number of subsets of 2 elements from a sample space of 12
= C(12,2) = 66
= C(12,2) = 66
n*(n-1)/2
66 people. Just do 132 / 2.
2 answers