If 100. mL of 0.400 M Na2SO4 is added to 200. mL of 0.600 M NaCl, what is the concentration of Na+ ions in the final solution? Assume that the volumes are additive.

Answer 1

moles Na2SO4 = M x L.
moles Na^+ = 2x that.

moles NaCl = M x L
moles Na^+ = 1x that.

M Na^+ = total moles Na^+/total volume in L.

Answer 2

Thank You got the right answer