heat gained by cool water + heat lost by warm water = 0
[mass cool H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass warm H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal, the only unknown in that string. But common sense tells you that you can average them, Tf should be 35 C. (You may average because it's the same material AND you started with equal volumes.)
If 100.0mL water of at 50.0C is added to 100.0 mL of water at 20.0C. What temperature would
the mixture of water reach? Assume the system is perfectly sealed and no heat is lost to the
calorimeter or to the outside environment.
2)
1 answer