21.2 g Na2CO3 = ? moles. moles = grams/molar mass
Then M = moles/L soln.
if 10 litres of a solution of na2co3 contains 21.2g of na2co3, what is its strength?
2 answers
Given, weight of na2co3(w)=21.2g
Volume of na2co3 solution (v)=10L
Strength (normality)=?
Now,
Normality=W/E*v=21.2/53*10=0.04N
Volume of na2co3 solution (v)=10L
Strength (normality)=?
Now,
Normality=W/E*v=21.2/53*10=0.04N
1 answer