If 10.00 g of water are introduced into an evacuated flask of volume 2.500 L at 65 degreed celcius, calculate the mass of water vaporized. (Hint: Assume that the volume of the remaining liquid water is negligible; the vapor pressure of water at 65 degrees celsius is 187.5 mmHg.)

Answer 1

you know pressure, volume, and temp. Solve for moles of water vapor.

PV=nRT

convert n to grams of H2O

Answer 2

n = (pv)/ (RT)
= (187.5 * 2.50) / (62.4 * 338) = 0.0222 mol H20

0.0222 mol H20 * 18.02g/mol = 0.4 g H20 vaporized