a^3=1/cos-cos = (1-cos^2)/cos=sin^2/cos
b^3=1/sin-sin = (1-sin^2)/sin=cos^2/sin
a^3/b^3=sin^2/cos * cos^2/sin=sin^3/cos^3
=>
a/b=sin/cos = tan
(Hope you understand your own notations.)
If 1/cos - cos=a^3 and 1/sin - sin=b^3
Show that tan=a/b
1 answer