If 1) a b 0 , 2) 0 a b , 3)b 0 a =0,
Where 1) ,2),3) represents the three rows of a (3*3) matrix which is equal to 0)
show that a/b is the cubic root of (-1).
I took b outside the matrix to get,
b* {1) (a/b) 1 0
2) 0 (a/b) 1
3) 1 0 (a/b) }
I don't see a way to proceed on.
1 answer
Take a look at the determinant of the matrix. It is (a^3+b^3)...