If 1.22 grams of N2 has a volume of 3.81L and a pressure of 5.49atm, what is its Kelvin Temperature?

Answer 1

1 mole occupies 22.4L, so you have 1.22/14 = 0.087 moles
Since PV/T = k, you want T such that

5.49*3.81/T = (1*0.087*22.4)/273

Answer 2

My bad. N2 has mass 28g, not 14
So adjust accordingly