If 1.20g of steam at 100.0 celcius condenses into 38.5 g of water, initially at 27 celcius what is final temperature of water

Answer 1

Note the correct spelling of celsius.
On condensation, the steam loses
q = mass steam x heat condensation.
That water will be at 100 C.
Then
[mass steam water x specific heat H2O x (Tfinal-Tinitial)] + [mass cool water x specific heat H2O x (Tfinal-Tinitial)] - q from condensation.
Substitute the numbers and solve for Tf. I estimated the Tf as about 45 or so.