No, the answer is not 0.08 M. The concentration of an aqueous solution is determined by dividing the moles of solute by the volume of the solution in liters.
Since the initial solution is 0.20 M NaCl, we can start by finding the moles of NaCl in 1.0 mL of the solution:
moles = concentration × volume
moles = 0.20 M × (1.0 mL / 1000 mL/L)
moles = 0.0002 moles
Next, we need to calculate the final volume of the solution. By dilution, the total volume of the solution is the sum of the initial volume (1.0 mL) and the volume of water added (2.5 mL), which gives us a total volume of 3.5 mL.
Finally, we can calculate the concentration of the new solution:
concentration = moles of solute / volume of solution
concentration = 0.0002 moles / (3.5 mL / 1000 mL/L)
concentration = 0.057 M
Therefore, the concentration of the new solution after dilution is 0.057 M, not 0.08 M.
If 1.0 mL of 0.20 M NaCl is diluted by addition of 2.5 mL water, calculate the M concentration of the new solution.
Is the answer not 0.08M ?
3 answers
or, since the volume has increased by a factor of 3.5, the concentration has decreased by the same factor:
0.2M / 3.5 = 0.057 M
0.2M / 3.5 = 0.057 M
You are correct. Apologies for the confusion in my previous response.
Since the volume has increased by a factor of 3.5 (from 1.0 mL to 3.5 mL), the concentration will decrease by the same factor when the solute is kept constant. Thus, the concentration of the new solution will be 0.2 M divided by 3.5, which equals 0.057 M.
Therefore, the concentration of the new solution after dilution is indeed 0.057 M. Thank you for pointing out the correct calculation!
Since the volume has increased by a factor of 3.5 (from 1.0 mL to 3.5 mL), the concentration will decrease by the same factor when the solute is kept constant. Thus, the concentration of the new solution will be 0.2 M divided by 3.5, which equals 0.057 M.
Therefore, the concentration of the new solution after dilution is indeed 0.057 M. Thank you for pointing out the correct calculation!
1 answer