If 0.48 g of sulfur are added to 200 g of carbon tetracholoride, and the freezing point of the carbon tetrachloride (Kf=30 degrees C/m) is depressed by 0.28 degrees C, what is the molar mass and molecular formula of the sulfur?

Question

.48g * 1mol/32.07g= .01497 mol S
.01497/.2 kg = .07485 molality
273.28K= i * 293K * .07485
i = .08
??

Answer 1

You aren't on the right track.

delta T = Kf*m
Solve for m

m = moles S/kg solvent
Solve for moles S.

moles S = grams S/molar mass SSolve for molar mass S.

part 2:
(molar mass S/32.066) = x
molecular formula = S_x

Answer 2

.28C = 30C * x/.2kg
x = .001867 moles S
.001867 moles S = .48g S/x
x = 8.0177 molecular formula for S

Is this correct?

Answer 3

S8 is the right formula for sulfur.