delta T = Kf*m
Solve for m
m = moles/kg solvent
solve for moles
moles = grams/molar mass
solve for molar mass.
If 0.48 g of sulfur are added to 200 g of carbon tetracholoride, and the freezing point of the carbon tetrachloride (Kf=30 degrees C/m) is depressed by 0.28 degrees C, what is the molar mass and molecular formula of the sulfur?
3 answers
thank you :)
.48g * 1mol/32.07g= .01497 mol S
.01497/.2 kg = .07485 molality
273.28K= i * 293K * .07485
i = .08
??
.01497/.2 kg = .07485 molality
273.28K= i * 293K * .07485
i = .08
??