If 0.48 g of sulfur are added to 200 g of carbon tetracholoride, and the freezing point of the carbon tetrachloride (Kf=30 degrees C/m) is depressed by 0.28 degrees C, what is the molar mass and molecular formula of the sulfur?

Answer 1

delta T = Kf*m
Solve for m

m = moles/kg solvent
solve for moles

moles = grams/molar mass
solve for molar mass.

Answer 2

thank you :)

Answer 3

.48g * 1mol/32.07g= .01497 mol S
.01497/.2 kg = .07485 molality
273.28K= i * 293K * .07485
i = .08
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