If 0.273 moles of ferrous ammonium sulfate (Fe(NH4)2(SO4)2 . 6H2O) and an excess of all other reagents are used in a synthesis of K2[Fe(C2O4)3] . 3H2O, how many grams of product will be obtained if the reaction gives a 100% yield?

Question

If 0.273 moles of ferrous ammonium sulfate  (Fe(NH4)2(SO4)2 . 6H2O) and an excess of all other reagents are used in a synthesis of K2[Fe(C2O4)3] . 3H2O, how many grams of product will be obtained if the reaction gives a 100% yield?
 Please help i found the molar mass of  (Fe(NH4)2(SO4)2 . 6H2O) = 491.1g/mol and
K2[Fe(C2O4)3] . 3H2O = 392.1 g/ mol.

DrBob222 · Answer

This is a stoichiometry problem. Here is a site that show you how to solve all "simple" stoichiometry problems (but not limiting reagent problems).
http://www.jiskha.com/science/chemistry/stoichiometry.html