If 0.176 g of pure sodium hydroxide was dissolved in water and the solution titrated with 5.05 mL of hydrochloric acid solution to a phenolphthalein end point, calculate each of the following of the hydrochloric acid solution.

Question

(a) the molarity = .871
(b) the percent by mass (density of solution = 1.016 g/mL)

Answer 1

mols NaOH = grams/molar mass = ?
a. 0.871 is correct for M.
b.
1.016 g/mL x 1000 mL x (?%/100) x (1/36.5) = 0.871
Solve for ?