AgIO3 ==> Ag^+ + IO3^-
Ksp = (Ag^+)(IO3^-)
Solubility
AgIO3 = grams/molar mass.
Plug that in for Ag^+ and for IO3^- and calculate Ksp.
If 0.0490g of AgIO3 DISOLVES per liter of solution, calculate the solubility product constant.
2 answers
1.73*10^-4