If 0.022 kg of ice at 0C is added to 0.450 kg of water at 80C, what is the final temperature. (Assume that there is no heat lost to the surroundings.)

Answer 1

sum of heats lost is zero.
-.022*Hf+.450*Cw(80-Tf)+.022(Cw)(0-Tf)=0
solve for Tf