Question

Idk how to do this! :(
Write an equation of the line that passes through the given point and is perpendicular to the given line (1,-1), y=3x+2

Answer 1

For a line to be perpendicular to another line you need to use m in the linear equation of y=mx+b and find the opposite and reciprocal of that number. In this case m is 3 so the opposite of 3 is -3 and the reciprocal is just flipping the fraction of -3/1 so it is now 1/-3. Now to find it going through a certain point you just take that 1/-3 and subtract it from -1 and you will get -2/3. So the answer is y=1/-3-2/3