To determine which expressions are equivalent to \(2x^2 - 8x - 10\) when distributed, we need to simplify each option.
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Option #1: \(2x(x - 4x - 5)\)
First, let's clarify the expression. It seems there is a typo or misplacement in the terms. Assuming it should be \(2x(x - 4) - 5\):
\[ 2x(x - 4) - 5 = 2x^2 - 8x - 5 \]
This expression does not equal \(2x^2 - 8x - 10\).
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Option #2: \((2x + 2)(x - 5)\)
Distributing gives:
\[ (2x + 2)(x - 5) = 2x^2 - 10x + 2x - 10 = 2x^2 - 8x - 10 \]
This expression equals \(2x^2 - 8x - 10\).
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Option #3: \(2x(x - 5) + 2(x - 5)\)
First, factor \( (x - 5) \):
\[ = (2x + 2)(x - 5) = 2x^2 - 10x + 2x - 10 = 2x^2 - 8x - 10 \]
This expression equals \(2x^2 - 8x - 10\).
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Option #4: \((x - 5)(x - 3)\)
Distributing gives:
\[ (x - 5)(x - 3) = x^2 - 3x - 5x + 15 = x^2 - 8x + 15 \]
This expression does not equal \(2x^2 - 8x - 10\).
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Option #5: \(-6x - 10\)
This is simply a linear expression and does not equal \(2x^2 - 8x - 10\).
Conclusion:
The equivalent expressions are:
- Option #2: \((2x + 2)(x - 5)\)
- Option #3: \(2x(x - 5) + 2(x - 5)\)
Given the requirement to enter the option with the lesser number first, the answer is:
Option #2 and Option #3.