Identify the vertex of y=4(x−25)2−61

Question

.(1 point)
Responses

(25,−61)
left parenthesis 25 comma negative 61 right parenthesis

(4,−25)
left parenthesis 4 comma negative 25 right parenthesis

(−25,−61)
left parenthesis negative 25 comma negative 61 right parenthesis

(−100,−61)

Answer 1

To identify the vertex of the quadratic function \( y = 4(x - 25)^2 - 61 \), we can compare it to the vertex form of a quadratic equation, which is \( y = a(x - h)^2 + k \), where \( (h, k) \) is the vertex.

In the given equation, we can see that:

• \( h = 25 \)
• \( k = -61 \)

Therefore, the vertex of the function is \( (25, -61) \).

So the correct response is:

(25, -61)