Identify the vertex of y=4(x−25)2−61

Question

.(1 point)
Responses

(25,−61)
left parenthesis 25 comma negative 61 right parenthesis

(−25,−61)
left parenthesis negative 25 comma negative 61 right parenthesis

(−100,−61)
left parenthesis negative 100 comma negative 61 right parenthesis

(4,−25)

Answer 1

None of the given options are the correct vertex.

The vertex of the quadratic function y = 4(x−25)2−61 is obtained by finding the values of x and y that make the expression inside the parentheses (x−25) equal to 0.

Set x−25 = 0 and solve for x:

x−25 = 0
x = 25

Substitute x = 25 into the equation to find y:

y = 4(25−25)2−61
y = 4(0)2−61
y = 0−61
y = -61

Therefore, the correct vertex is (25, -61).