identify the vertex of y = -10(x + 15)^2 - 18

1 answer

To identify the vertex of the quadratic function \( y = -10(x + 15)^2 - 18 \), we can use the vertex form of a quadratic equation, which is given by:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola.

In the given equation:

\[ y = -10(x + 15)^2 - 18 \]

we can rewrite the equation to match the vertex form:

\[ y = -10(x - (-15))^2 - 18 \]

Here, we can identify:

  • \( h = -15 \)
  • \( k = -18 \)

Thus, the vertex of the parabola is \((-15, -18)\).