Identify the vertex of y = -10(x + 15) ^2 - 18

1 answer

To identify the vertex of the quadratic function given in vertex form, we can use the general format of the vertex form of a parabola, which is:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola.

In your equation:

\[ y = -10(x + 15)^2 - 18 \]

we can rewrite it slightly to match the vertex form:

\[ y = -10(x - (-15))^2 - 18 \]

From this, we can see that:

  • \(h = -15\)
  • \(k = -18\)

Therefore, the vertex of the parabola is:

\[ (-15, -18) \]

So the vertex is \((-15, -18)\).