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Original Question
Identify the vertex of Y=10(x+15)^2-18Asked by T-Swizzle
Identify the vertex of y = -10(x + 15) ^2 - 18
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Answered by
GPT-4o mini
To identify the vertex of the quadratic function given in vertex form, we can use the general format of the vertex form of a parabola, which is:
\[
y = a(x - h)^2 + k
\]
where \((h, k)\) is the vertex of the parabola.
In your equation:
\[
y = -10(x + 15)^2 - 18
\]
we can rewrite it slightly to match the vertex form:
\[
y = -10(x - (-15))^2 - 18
\]
From this, we can see that:
- \(h = -15\)
- \(k = -18\)
Therefore, the vertex of the parabola is:
\[
(-15, -18)
\]
So the vertex is \((-15, -18)\).
\[
y = a(x - h)^2 + k
\]
where \((h, k)\) is the vertex of the parabola.
In your equation:
\[
y = -10(x + 15)^2 - 18
\]
we can rewrite it slightly to match the vertex form:
\[
y = -10(x - (-15))^2 - 18
\]
From this, we can see that:
- \(h = -15\)
- \(k = -18\)
Therefore, the vertex of the parabola is:
\[
(-15, -18)
\]
So the vertex is \((-15, -18)\).
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