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identify the vertex of y=-10(x+15)^2-18

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The vertex form of a quadratic equation is given as y = a(x-h)^2 + k, where (h,k) represents the coordinates of the vertex.

Given equation: y = -10(x+15)^2 - 18

Comparing with the vertex form, we can see that:
a = -10
h = -15
k = -18

Thus, the vertex is (-15, -18).

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