Identify the vertex of y=−10(x+15)2−18

Question

.(1 point)
Responses

(−10,−15)
left parenthesis negative 10 comma negative 15 right parenthesis

(−150,−18)
left parenthesis negative 150 comma negative 18 right parenthesis

(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis

(15,−18)

Answer 1

To identify the vertex of the quadratic function \( y = -10(x + 15)^2 - 18 \), we can observe the equation is in the vertex form of a parabola, which is:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola.

In the given equation, we can rewrite it to match the standard form:

\[ y = -10(x - (-15))^2 - 18 \]

From this form, we can see that \( h = -15 \) and \( k = -18 \). Therefore, the vertex of the parabola is:

\[ (-15, -18) \]

So the correct response is:

\((-15, -18)\)