Identify the vertex of y=−10(x+15)2−18.(1 point)

Question

Responses

(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis

(−10,−15)
left parenthesis negative 10 comma negative 15 right parenthesis

(15,−18)
left parenthesis 15 comma negative 18 right parenthesis

(−150,−18)

Answer 1

To identify the vertex of the quadratic function \( y = -10(x + 15)^2 - 18 \), we can recall that the vertex form of a quadratic equation is:

\[ y = a(x - h)^2 + k \]

where \( (h, k) \) is the vertex of the parabola.

In this case, the given equation can be rewritten as:

\[ y = -10\left(x - (-15)\right)^2 - 18 \]

From this, we can identify \( h \) and \( k \):

• \( h = -15 \)
• \( k = -18 \)

Thus, the vertex is \( (-15, -18) \).

The correct response is:

(−15,−18)