Identify the vertex of y=−10(x+15)2−18 .(1 point)

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Answer 1

The given quadratic function is in vertex form, which is \( y = a(x-h)^2 + k \), where \((h, k)\) represents the vertex of the parabola.

In your equation:

\[ y = -10(x + 15)^2 - 18 \]

Here, we can identify:

• \( h = -15 \) (since \( x + 15 \) means \( h = -15 \))
• \( k = -18 \)

Therefore, the vertex of the parabola is:

\[ (-15, -18) \]