identify the vertex of y= -10(c + 15)^2 - 18

Answer 1

To identify the vertex of the equation y = -10(c + 15)^2 - 18, we need to determine the value of c that results in the minimum value of y.

The vertex form of a quadratic equation is given by y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.

Comparing this with y = -10(c + 15)^2 - 18, we can see that h = -15 and k = -18.

Therefore, the vertex of the equation y = -10(c + 15)^2 - 18 is (-15, -18).