complete the square to change to vertex form
g(x) = x^2 + 8x + 11
= x^2 + 8x + 16 - 16 + 11
= (x+4)^2 - 5
vertex (-4,-5)
y=intercept is 11
x-intercept, gives us the zeros
let y = 0
(x+4)^2 - 5 = 0
(x+4)^2 = 5
x+4 = ± √5
x = -4 ± √5
Identify the vertex, intercepts, and zeros of the function.
g(x) = x^2 + 8x + 11
Please help!!
1 answer